A=(2,3,5,7,11)
B=(4,6,8,9,10,12)
C=(1,3,5,7,9,12)
VERIFY
AU(BnC)= (AUB) n (AUC)
Answers
Answered by
2
Answer:
BnC=(4,6,8,9,10,12)n(1,3,5,7,9,12)=(9,12)
AU(BnC)=(2,3,5,7,11)u(9,12)=(2,3,5,7,9,11,12)
Answered by
4
Step-by-step explanation:
Lhs:AU(BnC)
BnC=(4,6,8,9,10,12)n(1, 3,5,7,9,12)
=(9,12)
AU(BnC) =(2,3,5,7,11)U(9,12)
=(2,3,5,7,9,11,12)------->1
Rhs:(AUB) n(AUC)
AUB= (2,3,4,5,6,7,8,9,10,11,12)
AUC=(1,2,3,5,7,9,11,12)
(AUB) n(AUC) =(2,3,4,5,6,7,8,9,10,11,12)n(1,2,3,5,7,9,11,12)
=(2,3,5,7,9,11,12)-------->2
from 1&2
Lhs=Rhs
(I.e) AU(BnC) =(AUB) n(AUC)
Hence verified
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