Question

a/2+3=5solve equation ​

Answer 1

a/2 + 3 = 5

(a + 6) /2 = 5

a + 6 = 10

a = 4

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Answer 2

Solve the equation :-

$\sf\dfrac{a}{2} + 3 = 5$

Transposing 3 from LHS to RHS, changing its sign,

$\sf \dfrac{a}{2} = 5 - 3$

On simplifying,

$\sf \dfrac{a}{2} = 2$

Transposing 2 from LHS to RHS, changing its sign,

$\sf a = 2 \times 2$

On simplifying,

$\sf a = 4.$

So, the value of a is 4.

Verification :-

To check our answer, we just need to put 4 (The value of a) in place of a.

Putting 4 in place of a, we get :-

$\sf \dfrac{4}{2} + 3 = 5$

3 can also be written as 3/1, so,

$\sf \dfrac{4}{2} + \dfrac{3}{1} = 5$

The LCM of the denominators (2 and 1) is 2.

So we will put 2 as the denominator.

Now add the fractions.

$\sf\dfrac{(4 \times 1) + (3 \times2) }{ \: \: 2}$

On simplifying,

$\sf\dfrac{4 + 6 }{2}$

Adding, we get :-

$= \sf\dfrac{10}{2}$

10 and 2 are both divisible by 2, so reduce them.

We get :-

$\sf \dfrac{5}{1} = 5.$

$\sf5 = 5.$

Since LHS = RHS,

Hence verified! ✔️✔️