A=(2,-3) and B(-1,y)
is 5
If the distance between
B=(-1,4) is
5 units.
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can't understand your question
Answered by
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Answer:
A=(2,-3) B=(-1,y)
Distance From Ab = √ (x²-x¹)² + (y²-y¹)²
5=√ (-1-2)² + [y-(-3)]²
(5)²=(-3)² + (y+3)²
25 = 9 + [ (y)² +(3)² +2*y*3 ]
25-9 = y²+9+6y
16=y²+9+6y
16-9=y²+6y
7=y²+6y
y²+6y-7=0
y toh smjh ni aya phla part
nxt m apna bola B=(-1,4)
Now A=(2,-3) B=(-1,4)
Distance From AB = √ (x²-x¹)² + (y²-y¹)²
5 = √ (-1-2)² + [4-(-3)]²
(5)² = (-3)² +(4+3)²
25 = 9 + (7)²
25 = 9+49
25 = 58
LHS is not equal to RHS
wrong question
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