A={2,3} , B{0,1} , C{1,2} verify that A*(B union C)=(A*B)UNION(A*C)
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Answer:
A=2,3. B= 0,1. C=1,2
solving lhs
A(b union c)= 2,3(0,1 2)
so A( b union c) will be
(2,0) (2,1 ) (2,2 ) (3,0) ( 3,1) ( 3,2)
solving rhs
A×B = (2,0) (2,1) 3,0) (3,1)
A×C=(2,1) (2,2) (3,1) (3,2)
so A×B UNION A×C = (2,0) (2,1) (2,2) (3,0) (3,1) (3,2)
HENCE PROVED
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