a = - 2/3 b = 1/5 c = 2/7 Verify a x (b – c) = (a x b) – (a x c).
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Answered by
5
GIVEN :-
- a = -2/3
- b = 1/5
- c = 2/7
TO VERIFY :-
- a × (b - c) = (a × b) - (a × c)
VERIFICATION :-
⇒ a × (b - c) = (a × b) - (a × c)
Put the value of a , b and c.
L.H.S = a × (b - c)
⇒ -2/3 × (1/5 - 2/7)
⇒ -2/3 × [(7 - 10)/35]
⇒ -2/3 × [ -3/35 ]
⇒ -2/3 × -3/35
⇒ 6/105 -----------------------(1)
R.H.S = (a × b) - (a × c)
⇒ (-2/3 × 1/5) - (-2/3 × 2/7)
⇒ (-2/15) - (-4/21)
⇒ -2/5 + 4/21
⇒ -14/105 + 20/105
⇒ (-14 + 20)/105
⇒ 6/105 ------------------------(2)
From Equation (1) and (2)
L.H.S = R.H.S
HENCE VERIFIED ✔
Answered by
3
Answer:
Step-by-step explanation:
A ×B=![{1, 3, 5} × {2,3} = [{1, 2},{1, 3},{3, 2},{3, 3},{5, 2},{5, 3}] {1, 3, 5} × {2,3} = [{1, 2},{1, 3},{3, 2},{3, 3},{5, 2},{5, 3}]](https://tex.z-dn.net/?f=%7B1%2C+3%2C+5%7D+%C3%97+%7B2%2C3%7D+%3D+%5B%7B1%2C+2%7D%2C%7B1%2C+3%7D%2C%7B3%2C+2%7D%2C%7B3%2C+3%7D%2C%7B5%2C+2%7D%2C%7B5%2C+3%7D%5D)
B × A = ![{2, 3} × {1, 3, 5} = [{2, 1},{2, 3},{2, 5},{3, 1},{3, 3},{3, 5}] {2, 3} × {1, 3, 5} = [{2, 1},{2, 3},{2, 5},{3, 1},{3, 3},{3, 5}]](https://tex.z-dn.net/?f=%7B2%2C+3%7D+%C3%97+%7B1%2C+3%2C+5%7D+%3D+%5B%7B2%2C+1%7D%2C%7B2%2C+3%7D%2C%7B2%2C+5%7D%2C%7B3%2C+1%7D%2C%7B3%2C+3%7D%2C%7B3%2C+5%7D%5D)
A × A = ![{1, 3, 5} × {1, 3, 5}= [{1, 1},{1, 3},{1, 5},{3, 1},{3, 3},{3, 5},{5, 1},{5, 3},{5, 5}] {1, 3, 5} × {1, 3, 5}= [{1, 1},{1, 3},{1, 5},{3, 1},{3, 3},{3, 5},{5, 1},{5, 3},{5, 5}]](https://tex.z-dn.net/?f=%7B1%2C+3%2C+5%7D+%C3%97+%7B1%2C+3%2C+5%7D%3D+%5B%7B1%2C+1%7D%2C%7B1%2C+3%7D%2C%7B1%2C+5%7D%2C%7B3%2C+1%7D%2C%7B3%2C+3%7D%2C%7B3%2C+5%7D%2C%7B5%2C+1%7D%2C%7B5%2C+3%7D%2C%7B5%2C+5%7D%5D)
B × B =![{2, 3} × {2, 3} = [{2, 2},{2, 3},{3, 2},{3, 3}] {2, 3} × {2, 3} = [{2, 2},{2, 3},{3, 2},{3, 3}]](https://tex.z-dn.net/?f=%7B2%2C+3%7D+%C3%97+%7B2%2C+3%7D+%3D+%5B%7B2%2C+2%7D%2C%7B2%2C+3%7D%2C%7B3%2C+2%7D%2C%7B3%2C+3%7D%5D)
Note:
If either A or B are null sets, then A ×B will also be an empty set, i.e., if A = ∅ or
B = ∅, then A × B = ∅
hope it helps
:)
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