Question

A(2, 3), B(5, 4), C(6, 7) then ABC is
1) right angled isosceles
2) acute angled isosceles
3) obtuse angled isosceles
4)scalane​

Answer 1

Answer:

3. obtuse angled isosceles

Answer 2

Answer:

The Correct Answer Is Option 3

Step-by-step explanation:

AB²=(2-5)²+(3-4)²

=3²+1²

=9+1

=10

BC²=(5-6)²+(4-7)²

=1²+3²

=1+9

=10

AC²=(2-6)²+(3-7)²

=4²+4²

=16+16

=32

AB²+AC²=20

1)right angled isosceles=AB²+AC²=BC²

20≠32

so ABC is not right angled triangle ❌️

2)acute angled isosceles=AB²+AC²›BC²

But 20 is not greater than 32

so ABC is not actue angled triangle❌️

3)otuse angled isosceles=AB²+AC²‹BC²

20‹32

it is a obtuse angle

And two angles are also equal so it is also a isosceles triangle

so it is a obtuse angled isosceles✅️

So the correct option is 3.