Question

A 2.30-gram ice cube at water’s melting point is dropped into a glass of warm juice and gains enough joules of heat to melt completely. If the heat of fusion is 334 joules/gram, how much energy was absorbed in joules?

Answer 1

Answer:- 768 J of heat energy is absorbed.

Solution:- Mass of ice is 2.30 gram and it's going to melt means ice is changing to liquid and it's just a phase change where there is no change in temperature.

Heat of fusion is 334 joules per gram means 334 joules of heat is required to melt one gram of ice. We could multiply the grams by the heat of fusion to calculate the heat required for the given amount of ice.

$2.30g(\frac{334J}{1g})$

= 768.2 J

If they want answer with correct number of significant figures then it is round off to three significant figures and it becomes 768 J.

So, 768 J of heat was absorbed to melt 2.30 gram ice at it's melting point that is zero degree C.

Answer 2

Answer:

The answer is 768 for Plato users.

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