Question

a^2-3a+1=0 find a^2+1/a^2​

Answer 1

Answer:

Solving a2-3a-1 = 0 by the Quadratic Formula .

According to the Quadratic Formula, a , the solution for Aa2+Ba+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

a = ————————

2A

In our case, A = 1

B = -3

C = -1

Accordingly, B2 - 4AC =

9 - (-4) =

13

Applying the quadratic formula :

3 ± √ 13

a = —————

2

√ 13 , rounded to 4 decimal digits, is 3.6056

So now we are looking at:

a = ( 3 ± 3.606 ) / 2

Two real solutions:

a =(3+√13)/2= 3.303

or:

a =(3-√13)/2=-0.303

Answer 2

Answer:

3a + 1 / 3a

Step-by-step explanation:

a ^ 2 - 3a + 1 = 0

a^2 = 3a - 1

Now,

 a ^2 + 1 / a^2

PUT THE VALUE OF a^2 in equation.

= ( 3a - 1 ) + 1 / ( 3a - 1 )

= 3a - 1 + 1 / 3a - 1/1

= 3A - 1 + 1 / 3a - 0

= 3a + 1 / 3a