Question

(a^2+3a-5) ( a^2+3a+2) +6​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

a^2 ( a^2 + 3a + 2 ) + 3a ( a^2 + 3a + 2 ) - 5 ( a^2 + 3a + 2 ) + 6

a^2 ( a^2 + 3a + 2 ) + 3a ( a^2 + 3a + 2 ) - 5 ( a^2 + 3a + 2 ) + 6= a^4 + 3a^3 + 2a^2 + 3a^3 + 9a^2 + 6a - 5a^2 - 15a - 10 + 6

a^2 ( a^2 + 3a + 2 ) + 3a ( a^2 + 3a + 2 ) - 5 ( a^2 + 3a + 2 ) + 6= a^4 + 3a^3 + 2a^2 + 3a^3 + 9a^2 + 6a - 5a^2 - 15a - 10 + 6= a^4 + 6a^3 + 6a^2 + 21a - 4

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