Question

a^2-3a-54

factorise please

Answer 1

Answer:

a^2-3a-54

=a^2+6a-9a-54

=a(a+6)-9(a+6)

=(a-9)(a+6)

Answer 2

Answer:

I hope this will help you ☺️☺️

Step-by-step explanation:

a^{2} - 3a - 54a

2

−3a−54

Find two factor such that their sum is

-3a and product is -54

We know that -9×6=-54 and their sum is

-9+6=-3

So -9 and 6 are the numbers.

a^{2} - 9a + 6a - 54a

2

−9a+6a−54

a(a - 9) + 6(a - 9)a(a−9)+6(a−9)

(a - 9)(a + 6)(a−9)(a+6)

Now put

(a - 9) = 0(a−9)=0

a = 9a=9

Again put

(a + 6) = 0(a+6)=0

a = - 6a=−6

But your answer is to find the factor

So it's factor are

(a+ 6) \: and \: (a - 9)(a+6)and(a−9)