Question

A = (2, 5), B = (4, -11) and the locus of ‘C’ is 9x + 7y + 4 = 0 then the locus of the centroid of Δ ABC is

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Answer 1

$\huge\mathfrak{★ANSWER}$

$\huge\mathcal{ = 27x + 21y - 8 = 0}$

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$\huge\mathbb{★SOLUTION}$

Given:

A=(2,5) , B=(-4,11) and focus on C is 9x + 7y + 40...

Let the x-coordinate C is D.

So,

9x +7y +4 = 0

$y = \frac{9a - 4}{7}$

x- coordinate of centroid is

$y = \frac{5 - 11 \: \frac{9a - 4}{7} }{3}$

$3y = - 6 + ( \frac{ - 9(3x - 6) - 4}{7})$

$21y = - 42 - 27x + 54 - 4$

$27x + 21y + ( - 8) = 0$

$27x + 21y - 8 = 0$

$\large\mathcal{HOPE \: ITS \: HELPS \: YOU...}$

$\huge\mathfrak{@FFdevansh}$