A (2,5),B (6,-1)and C (-4,-3)are the vertices of triangle ABC.Find the equation of (1)the median though A. (2)the attitude through B.
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Midpoint on BC=[(6-4/2),(-1-3/2)]=(1,-2).
Equation through A to midpoint BC,
=>y+2=7/1*x-1=>y+2=7x-7=>7x-y-9=0 is the required equation for question (1)...,, for question (2),,
Midpoint on AC=[(2-4/2),(5-3/2)]=(-1,1).
Therefore equation of line B to midpoint on AC,,
=>y+1=(2/-1-6)*x-6=>-7y-7=2x-12.
=>2x+7y-5=0. Is the required equation!!
Equation through A to midpoint BC,
=>y+2=7/1*x-1=>y+2=7x-7=>7x-y-9=0 is the required equation for question (1)...,, for question (2),,
Midpoint on AC=[(2-4/2),(5-3/2)]=(-1,1).
Therefore equation of line B to midpoint on AC,,
=>y+1=(2/-1-6)*x-6=>-7y-7=2x-12.
=>2x+7y-5=0. Is the required equation!!
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