Question

a(-2,5)b(8,-4)c(7,10) check whether these points are collinear​

Answer 1

Answer:

they are not collinear.

I hope it is clear.

Answer 2

Answer:

Area of triangle =

$\frac{1}{2} [ x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]$

If the area of a triangle is zero, then the points are collinear.

Given,

a(-2,5)→a(x1,y1)

b(8,-4)→b(x2,y2)

c(7,10)→c(x3,y3)

Area of △ABC

$= \frac{1}{2} [ - 2( - 4 - 10) + 8(10 - 5) + 7(5 + 4)]$

$= \frac{1}{2} .28 + 40 + 63$

$= \frac{131}{2}$

Hence the given points are not collinear