Question

A 2.5 cm candle is placed 12 cm away from a convex mirror of focal length
30 cm. Give the location of the image and the magnification.

Answer 1

Answer:

as we know that ,,

Focal length (f) = 30 cm, object distance from the mirror (u) = -12 cm, height of object (ho) = 2.5 cm

We have to find the location of the image (v) and the magnification (m).

Mirror formula:

1/f = 1/v + 1/u

→ 1/30 = 1/v + 1/(-12)

→ 1/30 = 1/v - 1/12

→ 1/30 + 1/12 = 1/v

→ (2 + 5)/60 = 1/v

→ 7/60 = 1/v

→ 60/7 = v

→ 8.57 = v

so,

m = -v/u

m = -8.57/(-12)

m = 8.57/12

m = 0.71

Also, using formula

m = hi/ho, we can find the image height.

0.71 = hi/2.5

0.71(2.5) = hi

1.775 = hi

(Height of image (hi) = 1.775 cm)

Therefore, the location of the image from the mirror is 8.57 cm and it's magnification is 0.71.

THANK U AND MARKS AS BRAINLIEST !

Answer 2

Given:-

• Height of candle ,ho = 2.5cm

• Object distance, u = -12 cm

• Focal length ,f = 30cm

To Find:-

• Image distance ,v

• Magnification,m

Solution:-

Using mirror formula

• 1/v + 1/u = 1/f

Substitute the value we get

→ 1/v + 1/(-12) = 1/30

→ 1/v - 1/12 = 1/30

→ 1/v = 1/30 +1/12

→ 1/v = 2+5/60

→ 1/v = 7/60

→ v = 60/7 = 8.57cm

Therefore, the image location is 8.57 cm.

Now, Calculating the Magnification

magnification,m = hi/ho = -v/u

→ hi/2.5 = -60/7/-12

→ hi/2.5 = 0.71

→ hi = 0.71 ×2.5

→ hi = 1.77 cm

Therefore, the height of image is 1.77 cm

m = -v/u

→ m = -60/7/12

→ m = 0.71

Therefore, the magnification is 0.71 .