Question

A 2.5-kg bowling ball is thrown with a velocity of 10 m/s, what is its kinetic energy?

Answer 1

Answer:

• Kinetic energy is 125 J.

Given:

• Mass (m) = 2.5 kg
• Velocity (v) = 10 m/s

Explanation:

$\rule{300}{1.5}$

From the formula we know that,

$\longrightarrow{\sf{K.E\ =\ \dfrac{1}{2}mv^2}}$

Substitute the values,

$\longrightarrow{\sf{K.E\ =\ \dfrac{1}{2} \times 2.5 \times (10)^2}} \\ \\ \\ \longrightarrow{\sf{K.E\ =\ \dfrac{1}{2} \times 2.5 \times 10 \times 10}} \\ \\ \\ \longrightarrow{\sf{K.E\ =\ \dfrac{1}{2} \times 2.5 \times 100}} \\ \\ \\ \longrightarrow{\sf{K.E\ =\ \dfrac{1}{\cancel2} \times 2.5 \times \cancel{100}}} \\ \\ \\ \longrightarrow{\sf{K.E\ =\ 2.5 \times 50}} \\ \\ \\ \longrightarrow{\sf{K.E\ =\ 125\ J}}$

∴ The kinetic energy possessed by the ball is 125 J.

$\rule{300}{1.5}$