Question

A 2.5 L of nitrogen gas exerts a pressure of 760 mmHg at 473 K. What temperature is needed to reduce the volume to 1.75 L at 1140 torr?​

Answer 1

Given: 2.5 L of nitrogen gas exerts a pressure of 760 mmHg at 473 K

To Find: temperature is needed to reduce the volume to 1.75 L at 1140 torr

Solution:

= $\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

= $\frac{1140 x 1.75 x 473}{760}$× 2.5

= 496.65K

The temperature change is not very large. Most of the volume reduction comes from the increase in pressure.