Question

a 2.5 m wide path runs outside the boundary of a rectangular park of length 125 m and breadth 95 m. find the area of the path




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Answer 1

area of inner park=125m×95m
=11875m sq.unit
area of outer park=(125+5)×(95+5)
=130×100
=13000m sq.unit
so,area of path=area of o.p -area of i.p
=13000-11875
=1125m sq.unit

Answer 2

Step-by-step explanation:

Answer:

→ Area of the path = 861 m² .

Step-by-step explanation:

Given :-

→ Width of path = 3.5 m .

→ Side of square park along with path = 65 m .

To find :-

→ Area of the path .

Solution :-

∵ Side of square park without the path = 65 - ( 2 × 3.5 )  =  58 m .

Now, area of square park alnog with path

= side × side .

= ( 65 × 65 ) m² .

= 4225 m² .

And, area of square park without path

= side × side .

= ( 58 × 58 ) m² .

= 3364 m² .

Therefore, area of the path = ( 4225 - 3364 ) m² .

= 861 m² .

And, cost of measuring the rest of the field = 3364 × 25 .

= ₹86100 .

Hence, it is solved .

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