a^2 - 5b + ab - 25 factorise the following equation
Answers
Answered by
8
Hey Mate !
Here is your solution :
= a² - 5b + ab - 25
Rearranging the terms ,
= a² - 25 + ab - 5b
Taking out b as common from last 2 terms ,
= a² - 25 + b ( a - 5 )
= a² - 5² + b ( a - 5 )
Using identity :
[ ( a² - b² ) = ( a + b ) ( a - b ) ]
= ( a + 5 ) ( a - 5 ) + b ( a - 5 )
Taking ( a - 5 ) as common ,
= ( a - 5 ) ( a + 5 + b )
Rearranging the terms :
= ( a - 5 ) ( a + b + 5 ).
================================
Hope it helps !! ^_^
Here is your solution :
= a² - 5b + ab - 25
Rearranging the terms ,
= a² - 25 + ab - 5b
Taking out b as common from last 2 terms ,
= a² - 25 + b ( a - 5 )
= a² - 5² + b ( a - 5 )
Using identity :
[ ( a² - b² ) = ( a + b ) ( a - b ) ]
= ( a + 5 ) ( a - 5 ) + b ( a - 5 )
Taking ( a - 5 ) as common ,
= ( a - 5 ) ( a + 5 + b )
Rearranging the terms :
= ( a - 5 ) ( a + b + 5 ).
================================
Hope it helps !! ^_^
Anonymous:
If you liked my ans then mark as Brainliest plz..
Answered by
0
Answer:
hey mate here's your answer
hope it helps
Attachments:
Similar questions