Question

(a) -2, 6 (b) (-2,-6)
(C) 2,-6
Find the zeroes of Polynomial 6x²-3-7x
are​

Answer 1

SOLUTION :

=6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1)

⇒2x-3=0                                    or                            ⇒3x+1=0

⇒x=3/2                                       or                           ⇒ x= - 1/3

α=3/2 ,β= - 1/3

⇒α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

 ⇒αβ=c/a

 ⇒ 3/2(-1/3)= -7/6

⇒-1/2= -7/6

 ⇒1/2=7/6