Question

(a^2 - 6) x (a^3+ 3a - 4)​

Answer 1

Answer:

$( {a}^{2} - 6) \times ( {a}^{3} + 3a - 4)$

${a}^{2} ( {a}^{3} + 3a - 4) - 6( {a}^{3} + 3a - 4)$

${a}^{5} + 3 {a}^{3} - 4 {a}^{2} - 6 {a}^{3} - 18a + 24$

${a}^{5} - 3 {a}^{3} - 4 {a}^{2} - 18a + 24$

Answer 2

Step-by-step explanation:

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$(a 2 −6)×(a 3 +3a−4)$

${a}^{2} ( {a}^{3} + 3a - 4) - 6( {a}^{3} + 3a - 4)a2 (a 3 +3a−4)−6(a 3 +3a−4)$

${a}^{5} + 3 {a}^{3} - 4 {a}^{2} - 6 {a}^{3} - 18a + 24a$

$5 +3a 3 −4a 2 −6a 3 −18a+24$

${a}^{5} - 3 {a}^{3} - 4 {a}^{2} - 18a + 24a5−3a 3 −4a 2 −18a+24$