Physics, asked by SritamaFPal, 7 months ago

a 2.8 cm diameter coin is placed at a distance of 25cm from a concave lens that has a focal length of 12cm determine the image distance amd the diameter of the image​

Answers

Answered by akshayraff21
1

Answer:

Explanation:Answer: di = -8.11 cm and hi = 0.908 cm

Given: f = -12.0 cm and do = +25.0 cm and ho = 2.8 cm

Use the equation 1 / f = 1 / do + 1 / di

Substitute and solve for di.

1 / (-12.0) = 1 / (25.0) + 1 / di

1 / (-12.0) - 1 / (25.0) = 1 / di

-0.1233 cm-1 = 1 / di

di = 1 / (-0.1233 cm-1)

di = -8.11 cm

Then use hi / ho = - di / do to solve for hi.

hi / (2.8 cm) = - (-8.11 cm) / (25 cm)

hi = - (2.8 cm) • (-8.11 cm) / (25 cm)

hi = 0.908 cm

Answered by kramulu025
1

Answer:

0.0908cm

Explanation:

0.0908

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