Question

A 2.8 kg block of wood rests on a tabletop. A 8.7 g bullet moving horizontally with a speed of 130 m/s is shot into the block and sticks in it. The block then slides 266 cm along the table and stops. Find the speed of the block just after impact.

Answer 1

Explanation:

Momentum is equal before and after impact as it's conserved.

(mass of block) x (initial velocity) = (mass of block + mass of bullet) x (final velocity)

$m \times u = (m + bullet) \times v$

$v = \frac{2. \times 130}{2.8087}$

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