Question

a^2+8a+16 solve by spliting the middle term​

Answer 1

Given

a²+8a+16

To find

Factors of given polynomial

Solution

$\implies\red{a^2+8a+16}$

we have to break the middile term in such a way that the the sum become 8

And multiple be 16

Therefore

$\implies\green{a^2+4a+4a+16}$

$\implies\yellow{a(a+4)+4(a+4)}$

$\implies\brown{(a+4)(a+4}$

Hence the factor will be$\brown{(a+4)(a+4)}$

For extra information

The zeroes will be (-4,_4)

Answer 2

$\tt{ \red{ \implies{f(x) = {a}^{2} + 8a \: + 16}}}$

$\tt{ \red{ \implies{f(x) = {a}^{2} + 4a \: + 4a \: + 16}}}$

$\tt{ \red{ \implies{f(x) = a(a + 4) \: + 4(a \: + 4)}}} \\ \\ = \tt{ \purple{ {(a + 4)}^{2} }}$