Math, asked by thakur1212007, 3 months ago

a^2(a^2-2a+3)-5 and find its value for a=2​

Answers

Answered by Anjali5869
0

Answer:

The answer is 7

Step-by-step explanation:

  • a²(a²-2a+3)-5
  • (2)²((2)²-2(2)+3) -5
  • 4(4-4+3)-5
  • 8-8+12-5
  • 12-5
  • = 7
Answered by hemnagsai
0

Answer:

-4

Step-by-step explanation:

Given,

a^2(a^2-2a+3)-5

and also given,

a=2

so,

2^2(2^2-2(2)+3)-5

= 4(4-4+3)-5

= 4(4-7)-5

= 4(-3)-5

=4-3-5

= 4-8

=-4

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