Question

a^2/a^2×a^2



solve and verify 56+6t=44​

Answer 1

Answer:

i) 1/a² and ii) t= -2

Step-by-step explanation:

i) a²/a⁴ = 1/a²

ii) => 6t+56=44

=> 6t = -12

=> t = -2

verification =>

LHS:-

= 6(-2) + 56

=55-12

=44

RHS:-

44

THEREFORE, LHS=RHS

HENCE VERIFIED !!

hope it helped.

thanks !!

Answer 2

Answer:

Part 1:

1) There are two solutions because the question is a bit unclear.

First Solution:

$\dfrac{ \not{{a}^{2}} }{ \not{{a}^{2}} } \times {a}^{2} \\ \\ {a}^{2} \: \: \: \: \: \: \: \: \: \: \:$

Second Solution:

$\dfrac{ {a}^{2} }{ {a}^{2} \times {a}^{2} } \\ \\ \dfrac{ {a}^{2} }{ {a}^{4} } \: \: \: \: \: \: \: \: \: \: \\ \\ \dfrac{1}{ {a}^{2} } \: \: \: \: \: \: \: \: \: \:$

Part 2:

2) 56+6t=44

6t = -12

t = -2

Verification:

LHS

56+6*(-2)

56-12

44

LHS = RHS

Proved

Hope it helps u

Have a great day ahead

Take care and keep smiling

Annyeong