Question

(a+2)(a+3)(a+4)
simplify​

Answer 1

The question is already in its simplified form, Lets expand it

=>$(a+2)(a+3)(a+4)$

=>$(a^{2} + 3a + 2a + 2*3)(a+4)$

=>$(a^{2} + 5a + 6)(a+4)$

=>$a^{2} (a+4) + 5a(a+4) + 6(a+4)$

=>$a^{3}+ 4a^{2} + 5a^{2} +20a + 6a +24$

=>$a^{3}+9a^{2}+26a + 24$

Answer 2

Given,

$(a+2)(a+3)(a+4)$

We have to simplify the given expression

Here, we have to use distribution property of multiplication

• Distribution property of multiplication: The distribution property of multiplication states that multiplying two factors together gives the same result as breaking one factor up into two addends, multi[lying both addends with the remaining factor, then adding both products together.

Now,

$(a+2)(a+3)(a+4)$

We have to distribute first terms

$= (a(a+3)+2(a+3))(a+4)$

$= (a^{2}+3a+2a+6 )(a+4)$

$= (a^{2}+5a+6)(a+4)$

$= a(a^{2}+5a+6)+4(a^{2}+5a+6)$

$=(a^{3}+5a^{2} +6a)+(4a^{2}+20a+24)$

$=a^{3}+9a^{2} +26a+24$

Therefore, the answer is $a^{3}+9a^{2} +26a+24$.