Question

(a^2-a) ( 4a^2- 4a - 5) - 6​

Answer 1

Step-by-step explanation:

(a−2)(a+1)(4a

2

−4a+3)

(a

2

−a)(4a

2

−4a−5)−6

=(a

2

−a)[4(a

2

−a)−5]−6

Let (a

2

−a)=x

Thus,

x(4x−5)−6

=4x

2

−5x−6

=4x

2

−8x+3x−6

=4x(x−2)+3(x−2)

=(x−2)(4x+3)

Putting the value of x

=(a

2

−a−2)[4(a

2

−a)+3]

=(a

2

−2a+a−2)(4a

2

−4a+3)

=(a(a−2)+1(a−2))(4a

2

−4a+3)

=(a−2)(a+1)(4a

2

−4a+3)