Math, asked by reiraa, 18 days ago

a^2/(a−b)(a−c)+b^2/(b−c)(b−a)+c^2/(c−a)(c−b)

Answers

Answered by ragimishra
0

Step-by-step explanation:

a(b

2

+c

2

)+b(c

2

+a

2

)+c(a

2

+b

2

)+2abc

=ab

2

+ac

2

+bc

2

+ba

2

+ca

2

+cb

2

+2abc

=ba

2

+ca

2

+ab

2

+ac

2

+2abc+bc

2

+cb

2

=a

2

(b+c)+a(b

2

+c

2

+2bc)+bc(c+b)

=a

2

(b+c)+(b+c)

2

+bc(b+c)

=(b+c)[(a

2

+a(b+c)+bc]

=(b+c)[a

2

+ab+ac+bc]

=(b+c)[a(a+b)+c(a+b)]

=(b+c)(a+b)(a+c)

=(a+b)(b+c)(c+a)

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