Math, asked by nandasikka, 7 months ago

a^2- ab+b^2= if a+b= 10 and ab=18​

Answers

Answered by khushi7190
0

Answer:

As we know,

(a-b)^2=a^2+b^2–2ab

==>a^2+b^2=(a-b)^2+2ab———→(1)

(a+b)^2=a^2+b^2+2ab

on substituting eq(1) in above eq

(a+b)^2=(a-b)^2+4ab

(a+b)^2=(8)^2+4(9) as per in the question

(a+b)^2=64+36

(a+b)^2=100

by taking square on both sides

s0 a+b=10

a-b=8

a=8+b

ab=9

Therefore if a=8+b

(8+b)b=9

8b + b^2=9

b^2+8b-9=0

(b+9)*(b-1))=0

Therefore b=-9 OR b=1

If b=-9

a=8–9=-1

If b=1

a=8+1=9

Therefore a+b=9+1=10

OR

a+b=-1–9=-10

As a-b=8,ab=9

a=8+b

(8+b)b=9

8b+b^²=9

Solve the eqn using quadratic equationan u get

You get b^²+8b-9=0

So by solving we get

b=—9,+1.

a=8+(—9,1)

a=—1,9

a+b=—9–1=—10

1+9=10.

(a-b)^2 =a^2+b^2 -2ab

8x8=a^2+b^2 -2x9

64+18=a^2+b^2

So, a^2+b^2=82

Now,

(a+b)^2=a^2+b^2+2ab

(a+b) =√100

So a+b =10 {Ans}

(a+b)² = a² + 2ab + b² , and

(a - b)² = a² - 2ab + b² , so

(a + b)² = (a - b)² + 4ab

so, According to your question,

(a + b)² = 8² + 4 x 9 = 64 + 36 =

thus, a + b = √(100) = 10

I hope this helps

We are given that,

a-b=8

ab = 9

Now,

(a-b)² = a²+b² - 2ab

(8)²= a²+b² - 2(9)

64= a²+b² -18

64+18= a²+b²

a²+b²=82

Now,

(a+b)²= a²+b²+2ab

(a+b)²=82+2(9)

(a+b)²=82+18

(a+b)²=100

√{(a+b)²}=√100

a+b=+_10 (+ve, -ve 10)

It seems to be too simple.

The two numbers a & b are 9 & 1 respectively.

a - b = 8

9 - 1 = 8

Proved by trial and error method. No logic needed the amount was too small to assume hence.

Hope so the content was useful & Worthy.

As a-b= 8

=> a=8+b

ab =9

(8+b)b =9 {from above equations}

8b +b^2 =9

on solving this quadratic equation :

b=-9,1

so -9 and 1 is the answer

We will think of the numbers that if we multiply give the answer 9. These are 3 and 3, 9 and 1. We can see that if we subtract 9 and 1 we get 8. So, with 9 and 1 both the conditions are satisfied. a = 9 and b = 1. So, 9+1 will be 10.

Answer is 10

a-b=8

a=8+b…….(1)

ab=9

put value of a in above equation

(8+b)b=9

b²+8b-9=0………..[quadratic equation]

i.e b²+9b-b-9=0

b(b+9)-1(b+9)=0

(b-1)(b+9)=0

∴ b-1=0 or b+9=0

b=1 or b=-9

Its a rule to only take the positive one.

So taking b=1

a-b=8

So—a-1=8

Then a=9

So a+b=9+1=10.

The answer is 10.

Here,

a-b = 8 and ab = 9 —————(i)

As we know that (a-b)^2 = (a+b)^2 - 4(ab) ———(ii)

We have use this equation (ii) we get,

(8)^2 = (a+b)^2 - 4(9) {from equation (i)}

64 = (a+b)^2 - 36

(a+b)^2 = 64 + 36

(a+b)^2 = 100

(a+b) = +10 & -10 —————-(iii)

Hence, (a+b) = +10 &-10

We also find the value of a & b by using equati

Answered by tennetiraj86
2

Answer:

answer for the given problem is given

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