Question

A 2Ω and 3Ω resistances are connected in parallel to a battery of 6v. The current through 3Ω resistances is

Answer 1

If 2Ω and 3Ω resistors are connected in parallel with the battery, then each resistor will have same potential difference of 6V.

So, across 3Ω resistor, V = IR

I = 6V/ 3Ω = 2A

I = 2A

Answer 2

Given :

▪ Two identical resistors of resistances 2Ω and 3Ω are connected in parallel.

▪ Voltage of battery = 6V

To Find :

▪ Current through 3Ω resistor.

Concept :

☞ Potential difference remains same across all resistors in parallel connection.

☞ We can use ohm's law to calculate current flow through a resistor.

☞ As per ohm's law, current flow through a resistor is directly proportional to the applied potential difference.

Calculation :

$\dashrightarrow\tt\:V=I\times R\\ \\ \dashrightarrow\tt\:6=I\times 3\\ \\ \dashrightarrow\underline{\boxed{\bf{\purple{I=2A}}}}\:\orange{\bigstar}$