Question

a=2 and r=3 of GP find T4​

Answer 1

Answer:

54

Step-by-step explanation:

An=ar^n-1,so , A4= 2(3)^3= 52

Answer 2

Given,

The first term of a geometric progression = a = 2

The common ratio = r = 3

To find,

The fourth term (T4) of the G.P.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

For a G.P. with the first term a and common ratio d, its n-th term can be represented as;

n-th term of the G.P.= G(n) = a.r^(n-1){Statement-1}

Now, according to the question;

The value of T4 in the given G.P.

= T(4)

= a.r^(n-1)

= a.r^(4-1)

= (2)×(3)^3

= 2 × 27

= 54

Hence, the value of T4 in the given G.P. is equal to 54.