a^2+b^2 = 13 and ab = 6, find (i) a+b (ii) a-b
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Answer:
a+b=5
a-b=1
Step-by-step explanation:
a²+b²=13
ab=6
therefore,
(a+b)=√(a+b)²
=√{(a²+b²)+2ab}
=√{13+2×6}
=√(13+12)
=√25
=5
a-b=√(a-b)²
=√{(a²+b²-2ab)
=√(13-12)
=√1
=1
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