Question

a^2+b^2 = 13 and ab = 6, find (i) a+b (ii) a-b​

Answer 1

Answer:

a+b=5

a-b=1

Step-by-step explanation:

a²+b²=13

ab=6

therefore,

(a+b)=√(a+b)²

=√{(a²+b²)+2ab}

=√{13+2×6}

=√(13+12)

=√25

=5

a-b=√(a-b)²

=√{(a²+b²-2ab)

=√(13-12)

=√1

=1