a^2+b^2=131,ab=5 find (a-b)
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Answered by
4
(a - b)²= a² + b² - 2ab
Now putting the values, We get
(a - b)² = 131 - 2×5= 131 - 10 =121
Now putting the values, We get
(a - b)² = 131 - 2×5= 131 - 10 =121
Answered by
5
a²+b² = 131
ab = 5
a-b = ?
(a-b)² = a²+b²-2ab
= 131-10
(a-b)² = 121
(a-b) = 11
ab = 5
a-b = ?
(a-b)² = a²+b²-2ab
= 131-10
(a-b)² = 121
(a-b) = 11
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