Math, asked by manishpaswan813110, 1 year ago

a^2+b^2=221/100, ab=0.7, a^3+b^3=?​

Answers

Answered by sb93
0

Answer:

2.869

Step-by-step explanation:

a^{2}+b^{2}=2.21\\ab=0.7

\implies (a+b)^{2}=a^{2}+b^{2}+2ab

\implies (a+b)^{2}=2.21+2(0.7)

\implies (a+b)^{2}=2.21+1.4

\implies  (a+b)=\sqrt{3.61}

\implies a+b=1.9

Now substitute the values in + formula :

\implies  a^{3}+b^{3}=(a+b)(a^{2}+b^{2}-ab)

\implies a^{3}+b^{3}=(1.9)(2.21-0.7)

\implies \boxed{a^{3}+b^{3}=2.869}

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