a^2+b^2=29 and ab =10; find a+b and a-b
Answers
Answered by
4
A^2 + B ^2 = 29
(A)^2+(B)^2 +2AB-2AB=29-- (1)
(A+B)^2 -2AB= 29. ....
GIVEN ,
AB= 10
(A+B) ^2 - 2×10 = 29
(A+B)^2 = 9
A +B = √9
A+ B =3,
from (1)
(A-B)^2+2AB =29
( A- B) ^ 2 + 2× 10 =29
(A- B)^2=. 29-20
A - B = √9
A- B = 3
hence the value of A-B ,A+B = 3,3
(A)^2+(B)^2 +2AB-2AB=29-- (1)
(A+B)^2 -2AB= 29. ....
GIVEN ,
AB= 10
(A+B) ^2 - 2×10 = 29
(A+B)^2 = 9
A +B = √9
A+ B =3,
from (1)
(A-B)^2+2AB =29
( A- B) ^ 2 + 2× 10 =29
(A- B)^2=. 29-20
A - B = √9
A- B = 3
hence the value of A-B ,A+B = 3,3
lakshya8888:
Thanks for helping me
wc dear ! ty
Similar questions