Question

a^2 - b^2 - 2bc - c^2
​

Answer 1

Step-by-step explanation:

a²-b²+2bc-c² =a² - (b² -2bc +c²)

a²-b²+2bc-c² =a² - (b² -2bc +c²) =a² - (b-c)²

a²-b²+2bc-c² =a² - (b² -2bc +c²) =a² - (b-c)² =(a-(b-c))(a+(b-c)) [ using identity a²-b² =(a-b)(a+b) ]

a²-b²+2bc-c² =a² - (b² -2bc +c²) =a² - (b-c)² =(a-(b-c))(a+(b-c)) [ using identity a²-b² =(a-b)(a+b) ]

a²-b²+2bc-c² =a² - (b² -2bc +c²) =a² - (b-c)² =(a-(b-c))(a+(b-c)) [ using identity a²-b² =(a-b)(a+b) ] = (a-b+c)(a+b-c)

a²-b²+2bc-c² =a² - (b² -2bc +c²) =a² - (b-c)² =(a-(b-c))(a+(b-c)) [ using identity a²-b² =(a-b)(a+b) ] = (a-b+c)(a+b-c) hence.,a²-b²+2bc - c² = (a-b+c)(a+b-c)

Answer 2

Step-by-step explanation:

a²-b²-2bc-c²

a²-(b²+2bc+c²)

a²-{(b+c)²}

{a+(b+c)} {a-(b+c)}

(a+b+c) (a-b-c)

.....666......