(a^2+b^2)^3=(a^3+b^3)^2; a/b+b/a=?
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Answered by
4
a and b should be 1
so the answer shall be 2
so the answer shall be 2
fiercespartan:
siddartharao is the andwer right?
how?
ok
(a^2+b^2)^3=(a^3+b^3)^2;
It is in the form of (a+b)^3 and (a+b)^2
a^6 + b^6 + 3a^4b^2 + 3a^2b^4 = a^6 + b^6 + 2a^3b^3
3a^4b^2 + 3a^2b^4 = 2a^3b^3
on dividing with 3a^3b^3
a/b + b/a = 2/3.
It is in the form of (a+b)^3 and (a+b)^2
a^6 + b^6 + 3a^4b^2 + 3a^2b^4 = a^6 + b^6 + 2a^3b^3
3a^4b^2 + 3a^2b^4 = 2a^3b^3
on dividing with 3a^3b^3
a/b + b/a = 2/3.
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Answered by
8
(a^2+b^2)^3=(a^3+b^3)^2
=a^6+b^6+3a^2b^2(a^2+b^2)=a^6+b^6+2a^3b^3
=3a^2b^2(a^2+b^2)=2a^3b^3
=a^2+b^2=2/3ab
=(a^2+b^2)/ab=2/3
=a/b+b/a=2/3
=a^6+b^6+3a^2b^2(a^2+b^2)=a^6+b^6+2a^3b^3
=3a^2b^2(a^2+b^2)=2a^3b^3
=a^2+b^2=2/3ab
=(a^2+b^2)/ab=2/3
=a/b+b/a=2/3
nice work
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