Question

(A^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3

Answer 1

Answer:0

Step-by-step explanation:

a3+b3+c3=(a+b+c)[a2+b2+c2−ab−bc−ac]+3abc

*

Here a+b+c is 0*

Answer 2

Answer:

0

Step-by-step explanation:

(a^2-b^2+b^2-c^2+c^2-a^2)^3

(0)^3

0