Question

(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3/(a-b)^3+(b-c)^3+(c-a)^3 ​

Answer 1

Step-by-step explanation:

a^2-b^2+b^2-c^2+c^2-a^2=0

a-b+b-c+c-a=0

(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=3(a^2-b^2)(b^2-c^2)(c^2-a^2)

(a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a)

on dividing we get

3(a^2-b^2)(b^2-c^2)(c^2-a^2)/3(a-b)(b-c)(c-a)

=(a+b)(b+c)(c+a)