(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3/(a-c)^3+(b-c)^3+(c-a)^3
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Answered by
0
Answer:
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Step-by-step explanation:
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Answered by
1
Answer:
let a
2
−b
2
=x
1
;b
2
−c
2
=y
1
;c
2
−a
2
=z
1
x
1
+y
1
+z
1
=0
⇒x
1
3
+y
1
3
+z
1
3
=3x
1
y
1
z
1
=3(a
2
−b
2
)(b
2
−c
2
)(c
2
−a
2
)
let a−b=x
2
;b−c=y
2
;c−a=z
2
x
2
+y
2
+z
2
=0
⇒x
2
3
+y
2
3
+z
2
3
=3x
2
y
2
z
2
=3(a−b)(b−c)(c−a)
So,
x
2
3
+y
2
3
+z
2
3
x
1
3
+y
1
3
+z
1
3
=(a+b)(b+c)(c+a)
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