(a^2+b^2-4c^2)^2-4a^2b^2
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2
Answer:
(a
2
+b
2
−c
2
)
2
−4a
2
b
2
could also be written as:
(a^{2}+ b^{2} - c^{2} )^{2} -(2ab)^{2}(a
2
+b
2
−c
2
)
2
−(2ab)
2
As you can see It is in the form of a^2 -b^2
and as
a^{2} - b^{2} =(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
Therefore, by using this identity you'll get
= (a^{2}+ b^{2} - c^{2} -2ab) (a^{2}+ b^{2} - c^{2}+ 2ab )=(a
2
+b
2
−c
2
−2ab)(a
2
+b
2
−c
2
+2ab)
(a^{2}+ b^{2}-2ab - c^{2} ) (a^{2}+ b^{2}+2ab - c^{2} )(a
2
+b
2
−2ab−c
2
)(a
2
+b
2
+2ab−c
2
)
((a- b)^{2} - c^{2} ) ((a+ b)^{2} - c^{2} )((a−b)
2
−c
2
)((a+b)
2
−c
2
)
you can see that we need to use the same identity of a^2 -b^2 again
so, the whole thing becomes,
(a- b-c) (a-b+c) (a+ b-c)(a+b-c)(a−b−c)(a−b+c)(a+b−c)(a
Step-by-step explanation:
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