Math, asked by thakur2680, 9 months ago

(a^2+b^2-4c^2)^2-4a^2b^2​

Answers

Answered by saikrish88
2

Answer:

(a

2

+b

2

−c

2

)

2

−4a

2

b

2

could also be written as:

(a^{2}+ b^{2} - c^{2} )^{2} -(2ab)^{2}(a

2

+b

2

−c

2

)

2

−(2ab)

2

As you can see It is in the form of a^2 -b^2

and as

a^{2} - b^{2} =(a+b)(a-b)a

2

−b

2

=(a+b)(a−b)

Therefore, by using this identity you'll get

= (a^{2}+ b^{2} - c^{2} -2ab) (a^{2}+ b^{2} - c^{2}+ 2ab )=(a

2

+b

2

−c

2

−2ab)(a

2

+b

2

−c

2

+2ab)

(a^{2}+ b^{2}-2ab - c^{2} ) (a^{2}+ b^{2}+2ab - c^{2} )(a

2

+b

2

−2ab−c

2

)(a

2

+b

2

+2ab−c

2

)

((a- b)^{2} - c^{2} ) ((a+ b)^{2} - c^{2} )((a−b)

2

−c

2

)((a+b)

2

−c

2

)

you can see that we need to use the same identity of a^2 -b^2 again

so, the whole thing becomes,

(a- b-c) (a-b+c) (a+ b-c)(a+b-c)(a−b−c)(a−b+c)(a+b−c)(a

Step-by-step explanation:

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