Question

A^2 - B^2 =9×11 find the value of A and B?

Answer 1

Answer:

A= 10  , B= -1

Step-by-step explanation:

$A^2 - B^2 =9*11$

$(a+b) (a-b) = a^{2} - b^{2}$

$A^2 - B^2$ = (A+B) (A-B)

(A+B) (A-B) = 9*11

Comparing Both Side

So,

A+B = 9     and       A-B = 11

A+B = 9 --(1)

A-B = 11 --(2)

Subtract (1) and (2)

             $A+B = 9\\     A-B = 11\\     ------------------\\    2A = 20$

    A= 20/2

   A = 10 --Put in (1)

  A+B = 9 --(1)

  B = 9 - A

  B = 9 - 10

  B = -1