Question

a^2+b^2+9c^2+2ab-4ac+6bc factorise​

Answer 1

➸ Solution:

$→\;\sf{a²+b²+9c²+2ab-4ac+6bc}$

$→\;\sf{a²+b²+3²c²+2ab-4ac+6bc}$

$→\;\sf{a²+b²+(3c)²+2(ab-2ac+3bc)}$

• $\red{\bold{a²+b²+(3c)²+2(ab-2ac+3bc)}}$

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