Question

(a^2-b^2)(a^2+b^2)(a^2-b^2)^2

Answer 1

a^2+b^2+a^-2+b^-2 = 4

=> ((a^2+a^(-2) – 2)+(b^2+b^(-2) -2))+4 = 4

=> (a-(1/a))^2 + (b-(1/b))^2 = 0

=> a - (1/a) = 0 and b - (1/b) = 0

=> a = 1/a and b = 1/b

=> a^2 = 1 and b^2 = 1

So a^2 - b^2 = 0.

The answer is 0

hope that help you