Math, asked by sarudas965, 8 months ago

(a^2-b^2)(a^2+b^2)(a^4+b^4)-(a^8-b^8)​

Answers

Answered by adithyasathishkumar
1

Answer:

(a²-b²)(a²+b²)(a⁴+b⁴)-(a^8-b^8)

(a⁴-b⁴)(a⁴+b⁴)-(a^8-b^8)

(a^8-b^8)-(a^8-b^8)=0

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