Question

(a^2 + b^2 ) (-a^2+b^2) Please solve it!!

Answer 1

Answer- Given- (a²+b²) (-a²+b²)

Solution- (a²+b²) (-a²+b²) can be solved by multiplication.

= a²(-a²+ b²) +b²(-a²+b²)

= -a⁴+ a²b² - a²b² + b⁴

a²b² - a²b² will get cut.

= -a⁴ + b⁴

OR

= b⁴ - a⁴

Checking-->

Factorise b⁴-a⁴

= (b²)² - (a²)²

= (b²+a²) (b²-a²) [Using x²-y²= (x+y)(x-y) where x= b² and y= a²]

OR

= (a²+b²) (-a²+b²)

Please mark as the BRAINLIEST answer if helpful.

Answer 2

Hey there! Thanks for the question .

This question can be solved by multiplication, but let's look for something interesting other than that. I will do the multiplication also for you!

( a² + b² ) ( -a² + b² )

Taking negative out from the second term,

= - ( a² + b² ) ( a² - b²)

This is now in the form of (m + n) ( m-n) = m²- n²

So,

= -[ ( a²)² - (b²)² ]

$= - ( {a}^{4} - {b}^{4} )$

= ${b}^{4 } - {a}^{4}$

So , This is our answer.

Let's try out with multiplication now,

(a² + b² ) ( -a² + b² )

= a² ( -a² + b² ) + b² ( -a² + b² )

= -a^4 + a²b² - a²b² + b^4

$= - {a}^{4} + {b}^{4}$

Hope helped!