Question

a^2-b^2-a-b factorise​

Answer 1

Here's the Factorisation:

${a}^{2} - {b}^{2} - a - b \\ \\ = (a - b)(a + b) - (a + b) \\ \\ = (a + b)((a - b) - 1)) \\ \\ = (a + b)(a - b - 1)$

Thus factorized

Answer 2

Answer:

Answer:

Given:

a² - b²-a - b

Solving Question:

•  We are given the expression ,which we have to factorise.

Solution:

•  $a^2-b^2-a-b$

Recall the identity : a² - b² = (a+b)(a-b)

⇒ (a +b)(a-b) -1(a+b) = 0

Take out (a+b)

⇒ (a+b) [ a-b-1] = 0

⇒ a + b = 0

⇒ or, a-b = 1

let's find the values

a-b = 1

a + b = 0

......................

2a = 1

a = 1/2

a - b = 1

1/2 - b = 1

⇒ -b = 1/2

⇒ b = -1/2

Hence, the value of a = 1/2 and b = -1/2