Question

a^2+b^2+c^2+27=6(a+b+c) then find the value of 3√a^3+b^3-c^3​

Answer 1

Answer:

a²+b²+c²+27=6(a+b+c) ► (a² -6a+9) + (b² -6b+9) +(c² -6c+9)=0 ►(a-3)²+(b-3)²+(c-3)²=0 which, in turn, implies that a=3, b=3 & c=3 and thus (a³+b³-c³)^(1/3) =(3³)^(1/3) =3