Question

a^2+b^2+c^2=89, ab+bc+ca=40, find a+b+c​

Answer 1

Answer:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

= 89+2(40)

= 89+80=169

a+b+c=√169 = 13

Answer 2

Step-by-step explanation:

we know... (a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)

(a+b+c)^2 = 89+2*40

(a+b+c)^2 =89+80

(a+b+c)^2 =169

therefore a+b+c=✓169

a+b+c= 13

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