Question

(a^2 +b^2 + c^2)a+b+c = (b+p)/1


solve for p

Answer 1

$(a^2 +b^2 + c^2)a+b+c =\dfrac{b+p}{1}\\\\(a^2 +b^2 + c^2)a+b+c =b+p\\\\p=(a^2 +b^2 + c^2)a+b+c -b\\\\p=(a^2 +b^2 + c^2)a+c$